2x^2+4x+12=3

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Solution for 2x^2+4x+12=3 equation:


Simplifying
2x2 + 4x + 12 = 3

Reorder the terms:
12 + 4x + 2x2 = 3

Solving
12 + 4x + 2x2 = 3

Solving for variable 'x'.

Reorder the terms:
12 + -3 + 4x + 2x2 = 3 + -3

Combine like terms: 12 + -3 = 9
9 + 4x + 2x2 = 3 + -3

Combine like terms: 3 + -3 = 0
9 + 4x + 2x2 = 0

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
4.5 + 2x + x2 = 0

Move the constant term to the right:

Add '-4.5' to each side of the equation.
4.5 + 2x + -4.5 + x2 = 0 + -4.5

Reorder the terms:
4.5 + -4.5 + 2x + x2 = 0 + -4.5

Combine like terms: 4.5 + -4.5 = 0.0
0.0 + 2x + x2 = 0 + -4.5
2x + x2 = 0 + -4.5

Combine like terms: 0 + -4.5 = -4.5
2x + x2 = -4.5

The x term is 2x.  Take half its coefficient (1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
2x + 1 + x2 = -4.5 + 1

Reorder the terms:
1 + 2x + x2 = -4.5 + 1

Combine like terms: -4.5 + 1 = -3.5
1 + 2x + x2 = -3.5

Factor a perfect square on the left side:
(x + 1)(x + 1) = -3.5

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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